A Berkeley Review passage asks how much water would be produced from the complete oxidation of 1 mole of caprylic acid (8 carbon saturated fatty acid). The answer states that 8 net H20 would be produced, however using the method that Lehningers Biochem teaches on p. 675 I got 11 H20. Can anyone confirm if I did it correctly and if TBR is wrong?:
Step 1: 3 rounds of B-ox produces 4 acetyl CoA, 3 NADH, 3 FADH2, and wastes 3H2O; according to Lehninger's p.675, 1 H2O is produced per 2 electron...
Net water produced from complete oxidation of an 8 carbon saturated fatty acid
Step 1: 3 rounds of B-ox produces 4 acetyl CoA, 3 NADH, 3 FADH2, and wastes 3H2O; according to Lehninger's p.675, 1 H2O is produced per 2 electron...
Net water produced from complete oxidation of an 8 carbon saturated fatty acid